A case has a wheel lock combination-three years, and each wheel is numbered zero through nine ...? How many possible combinations are there? And what are the odds against finding the right combination?
There are thousands of combinations in the game, so we can say that chances are one in a thousand that you want to find the right first time, but in fact would be easy enough to try them all. If a briefcase has two of these locks, however, that many do (each with its own combination), the most difficult --- but again, it's really not. You open the first lock, rolling through thousands of combinations, then leave it open while you run through thousands of combinations of the second lock.
As there are 10 digits can be selected in each wheel:
10 * 10 * 10 = 1000
There are 1,000 different combinations.
the probability of randomly selecting the combination is 1 / 1000, or 0,001
llaffer copied my answer
As there are 10 digits can be selected in each wheel:
10 * 10 * 10 = 1000
There are 1,000 different combinations.
the probability of randomly selecting the combination is 1 / 1000, or 0,001
As there are ten choices for each wheel and three wheel, there are 10 ^ 3 or 1000 different combinations. The probability of choosing the right combination of 1 / 1000 so the odds against finding the correct combination is 999 to 1 (999:1).
Posted on May 17, 2010.